I'm not sure you can get there with that route.
mols glucose needed = 4 M x 0.400 L = ?
Then mols = grams/molar mass. You know mols and molar mass, solve for grams.
You need to prepare 400 ml of a 4M glucose solution. It's chemical formula is C6H12O6 and its formula weight (FW) 180.16. Must show all work and calculation and then list what you will mix together to prepare the correct amount of this solution.
180.16 of glucose/400ml = x/4M
400*x 180.16*4
400x = 720.64
400/400
720.64/400 = 1.80
x= 1.80
I don't know where to go from here.
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