There are 12 letters in total, and we need to find the probability of selecting a vowel. Counting the vowels (A, E, I, O, U), we see that there are 3 vowels. Therefore, the probability of selecting a vowel is 3 out of 12, or 1/4. However, the answer choices are all fractions, so we need to simplify 1/4:
1/4 = 3/12 = 5/20
Now we see that the answer in simplest form is option:
$\boxed{\textbf{(C) } \frac{1}{3}}$
You mix the letters S, E, M, I, T, R, O, P, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability that you select a vowel. Write your answer as a fraction in simplest form.
A. twelve-fifths
B. Start fraction 5 over 12 End fraction
C. start fraction 1 over 3 end fraction
D. start fraction 7 over 12 end fraction
9 answers
You roll a standard number cube once. Find P(0).
A. The term shows 7 over 6.
B. 1
C. one-half
D. 0
A. The term shows 7 over 6.
B. 1
C. one-half
D. 0
A standard number cube has sides numbered 1, 2, 3, 4, 5, and 6. We want to know the probability of rolling a 0. However, 0 is not a possible outcome of rolling a number cube, so the answer is $\boxed{\textbf{(D) }0}$.
Use the following information for problems 3 and 4.
From a barrel of colored marbles, you randomly select 7 blue, 5 yellow, 8 red, 4 green, and 6 purple marbles.
Find the experimental probability of randomly selecting a marble that is not yellow. Write your answer in simplest form.
A. start fraction 1 over 30 end fraction
B. five-sixths
C. start fraction 2 over 15 end fraction
D. start fraction 1 over 6 end fraction
From a barrel of colored marbles, you randomly select 7 blue, 5 yellow, 8 red, 4 green, and 6 purple marbles.
Find the experimental probability of randomly selecting a marble that is not yellow. Write your answer in simplest form.
A. start fraction 1 over 30 end fraction
B. five-sixths
C. start fraction 2 over 15 end fraction
D. start fraction 1 over 6 end fraction
There are a total of 7+5+8+4+6 = 30 marbles, of which 5 are yellow. To find the probability of selecting a non-yellow marble, we need to first determine the total number of non-yellow marbles. This is 30 - 5 = 25.
Therefore, the experimental probability of randomly selecting a non-yellow marble is:
$\frac{\text{number of non-yellow marbles}}{\text{total number of marbles}} = \frac{25}{30} = \frac{5}{6}$
So the answer is $\boxed{\textbf{(B) } \frac{5}{6}}$.
Therefore, the experimental probability of randomly selecting a non-yellow marble is:
$\frac{\text{number of non-yellow marbles}}{\text{total number of marbles}} = \frac{25}{30} = \frac{5}{6}$
So the answer is $\boxed{\textbf{(B) } \frac{5}{6}}$.
From a barrel of colored marbles, you randomly select 7 blue, 5 yellow, 8 red, 4 green, and 6 purple marbles.
Find the experimental probability of randomly selecting a marble that is either green or purple. Write your answer in simplest form.
A. one-tenth
B. one-fifth
C. one-third
D. two-fifteenths
Find the experimental probability of randomly selecting a marble that is either green or purple. Write your answer in simplest form.
A. one-tenth
B. one-fifth
C. one-third
D. two-fifteenths
The total number of green and purple marbles is 4+6 = 10. To find the probability of selecting a green or purple marble, we need to divide the number of green and purple marbles by the total number of marbles:
$\frac{\text{number of green or purple marbles}}{\text{total number of marbles}} = \frac{10}{30} = \frac{1}{3}$
So the answer is $\boxed{\textbf{(C) } \frac{1}{3}}$.
$\frac{\text{number of green or purple marbles}}{\text{total number of marbles}} = \frac{10}{30} = \frac{1}{3}$
So the answer is $\boxed{\textbf{(C) } \frac{1}{3}}$.
Clarissa is having lunch at a sandwich shop. She can choose white bread or pumpernickel bread. Her options for fillings are turkey, tuna, ham, or egg salad. Her choices for condiments are mayonnaise, salad dressing, or mustard. How many different sandwich choices does Clarissa have?
A. 36
B. 6
C. 24
D. 12
A. 36
B. 6
C. 24
D. 12
Clarissa has 2 choices for bread, 4 choices for fillings, and 3 choices for condiments. To find the total number of different sandwich choices, we multiply these numbers together:
$2 \times 4 \times 3 = 24$
So Clarissa has $\boxed{\textbf{(C) }24}$ different sandwich choices.
$2 \times 4 \times 3 = 24$
So Clarissa has $\boxed{\textbf{(C) }24}$ different sandwich choices.