You mix the letters M,A,T,H,E,M,A,T,I,C,A and L, thoroughly, Without looking , you draw one letter. Find the probability P(A). Write the probability as:
A) fraction in simplest form
B) a decimal
C) a percent
there are 3 letter A"s, so my answers are
A)1/4
B).25
C) 25%
can you check my answer?
Thanks
46 answers
You are right.
what is the equation idk if i spelt it right or how did you figure it out
お、オは、日本語の音節の1つであり.
Oh, one of the Japanese syllables
Oh, is one of the Japanese syllables. Thats what he said XD
this is the last question at connexus for math in 6th grade!!!!!!!!!!!!!
Ew yep
@NANI!?!??!
おい、あなたは今真剣ですか？私たちは答えが必要です。しかし、私たちはここでエイトします。
Translation:
Dude, are you serious right now? WE NEED ANSWERS. But we aight here.
おい、あなたは今真剣ですか？私たちは答えが必要です。しかし、私たちはここでエイトします。
Translation:
Dude, are you serious right now? WE NEED ANSWERS. But we aight here.
迷子にしないでください
hey ~"😂" your emoji ain't cool anymore...
and~ 迷子に 真剣ですか？私たち節の1つであり日本語の音節?
あなたは今真剣ですか!!!
あなたは今真剣ですか!!!
<&> ^<&> J K I D E K W T S (my secret wording)
but it pretty easy to figure out &^& >O< if you have done it before. reeeeeeeeeeeeeeeeeeeeeenoooooooooooooooooooooooooooo IK right!
but it pretty easy to figure out &^& >O< if you have done it before. reeeeeeeeeeeeeeeeeeeeeenoooooooooooooooooooooooooooo IK right!
wow, whoa, holy moly, holy cow, oh my stars, what is all of this?!
thanks for the right answer tho gal you awesome!!
thanks for the right answer tho gal you awesome!!
Man, y'all have to much fun on this website. lmfao
so i got some of it? not all of it right?
yea i got some of it good job dude.
sorry, I meant yea you got some of it not me.
*Visible Confusion*
EXPLAIN PLEASE I AM SO LOST
I would like if someone would just tell me the dang answer
I- y'all are having too much fun (￣y▽,￣)╭
- gogy.com
- gogy.com
I JUST WASNTED ANSWERS -.-
Hey guys the answer should be
A. 3/12 = 1/4
B. 0.25
C. 25%
Let me know if I made a mistake somewhere!
A. 3/12 = 1/4
B. 0.25
C. 25%
Let me know if I made a mistake somewhere!
pinche maricon wey
No voy desir nada @SantanaDiffrente
夢のsmp伝承を見ている人
5 years and no one has answered this question
at least this is faster than our game updates its been 6 years senes our last update
JAMIE 5 years later reading the answers: 👁👄👁.
何してるの？
ENOUGH WITH THE JAPANESE
this is the last d@mn math question for the year, im not trying to go through heII rn..
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability P(A). Write the probability as:
a. a fraction in simplest form
b. a decimal
c. a percent
a. a fraction in simplest form
b. a decimal
c. a percent
The given set of letters in the word is "MATHMATICAL."
There are two "A"s in the given word.
a. The probability of selecting "A" is 2/12, which simplifies to 1/6.
b. The probability is 0.1667.
c. The probability is 16.67%.
There are two "A"s in the given word.
a. The probability of selecting "A" is 2/12, which simplifies to 1/6.
b. The probability is 0.1667.
c. The probability is 16.67%.
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
There are six possible outcomes when rolling a number cube, which are {1, 2, 3, 4, 5, 6}. Since we are rolling the number cube twice, the total number of possible outcomes is 6 × 6 = 36.
The events "even" and "not 2" are independent and can occur in either order. Thus, we can calculate the probability of rolling an even number on the first roll and a non-2 number on the second roll as:
P(even, then not 2) = P(even) × P(not 2)
P(even) = favorable outcomes / total outcomes = 3 / 6 = 1/2 (since there are three even numbers: 2, 4, 6)
P(not 2) = favorable outcomes / total outcomes = 5 / 6 (since there are five non-2 numbers: 1, 3, 4, 5, 6)
So, P(even, then not 2) = (1/2) × (5/6) = 5/12. Therefore, the probability of rolling an even number on the first roll and a non-2 number on the second roll is 5/12 when rolling a number cube twice.
The events "even" and "not 2" are independent and can occur in either order. Thus, we can calculate the probability of rolling an even number on the first roll and a non-2 number on the second roll as:
P(even, then not 2) = P(even) × P(not 2)
P(even) = favorable outcomes / total outcomes = 3 / 6 = 1/2 (since there are three even numbers: 2, 4, 6)
P(not 2) = favorable outcomes / total outcomes = 5 / 6 (since there are five non-2 numbers: 1, 3, 4, 5, 6)
So, P(even, then not 2) = (1/2) × (5/6) = 5/12. Therefore, the probability of rolling an even number on the first roll and a non-2 number on the second roll is 5/12 when rolling a number cube twice.
shorter
The probability of rolling an even number on the first roll is 1/2 (since there are three even numbers out of six total). The probability of rolling a non-2 number on the second roll is 5/6 (since there are five non-2 numbers out of six total). So, the probability of rolling an even number first, then not 2 is (1/2) × (5/6) = 5/12.
shorter
The probability of rolling an even number first and a non-2 number second is 5/12.
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Marissa is researching information about martial arts students. She found that 7 out of 12 martial artists practice every day. There are 144 martial arts students at a school.
a. Predict how many students practice every day.
b. What is the sample size?
Marissa is researching information about martial arts students. She found that 7 out of 12 martial artists practice every day. There are 144 martial arts students at a school.
a. Predict how many students practice every day.
b. What is the sample size?
a. If 7 out of 12 martial artists practice every day, we can predict that the same proportion of students in the school would practice every day.
The number of martial arts students who practice every day can be calculated as:
7/12 * 144 = 84
Therefore, we can predict that 84 martial arts students practice every day.
b. The sample size is the total number of martial arts students in the school, which is 144.
The number of martial arts students who practice every day can be calculated as:
7/12 * 144 = 84
Therefore, we can predict that 84 martial arts students practice every day.
b. The sample size is the total number of martial arts students in the school, which is 144.
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability P(A). Write the probability as:
a. a fraction in simplest form
b. a decimal
c. a percent
a. a fraction in simplest form
b. a decimal
c. a percent
To find the probability of drawing the letter "A" from the given set of letters, we need to first count the number of "A"s in the set.
There are three "A"s in the set: one at the second position, one at the seventh position, and one at the eleventh position.
a. The probability of drawing an "A" from the set is the number of "A"s in the set divided by the total number of letters in the set:
P(A) = 3/12 = 1/4 (simplified to lowest terms)
b. The decimal equivalent of 1/4 is 0.25.
c. The percentage equivalent of 1/4 is 25%.
There are three "A"s in the set: one at the second position, one at the seventh position, and one at the eleventh position.
a. The probability of drawing an "A" from the set is the number of "A"s in the set divided by the total number of letters in the set:
P(A) = 3/12 = 1/4 (simplified to lowest terms)
b. The decimal equivalent of 1/4 is 0.25.
c. The percentage equivalent of 1/4 is 25%.
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter.
Find the probability P(A). Write the probability as:
a. a fraction in simplest form
b. a decimal
c. a percent
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter.
Find the probability P(A). Write the probability as:
a. a fraction in simplest form
b. a decimal
c. a percent
There are 12 letters in the given set, out of which 3 are "A"s.
a. The probability of drawing an "A" is the ratio of the number of "A"s in the set to the total number of letters in the set.
So, P(A) = number of "A"s/total number of letters = 3/12
We can reduce the fraction 3/12 to its simplest form by dividing the numerator and denominator by their greatest common factor, which is 3.
Therefore, P(A) = 3/12 = 1/4 (fraction in simplest form).
b. The decimal value of 1/4 is 0.25.
c. The percentage value of 1/4 is 25%.
a. The probability of drawing an "A" is the ratio of the number of "A"s in the set to the total number of letters in the set.
So, P(A) = number of "A"s/total number of letters = 3/12
We can reduce the fraction 3/12 to its simplest form by dividing the numerator and denominator by their greatest common factor, which is 3.
Therefore, P(A) = 3/12 = 1/4 (fraction in simplest form).
b. The decimal value of 1/4 is 0.25.
c. The percentage value of 1/4 is 25%.
1 answer