height=velocitysound*time
so figure the velocity of sound at 23C
You look up and see a helicopter pass directly overhead: 3.10-s later you hear the sound of the engines. If the air temperature is 23.0°C, How high was the helicopter flying?
3 answers
1068.88m
d=distance v=velocity t=time
d = vt
331+0.6 (23) = 354.6
354.6 * 3.10 = 1068.88m
d = vt
331+0.6 (23) = 354.6
354.6 * 3.10 = 1068.88m