you invested $8000 between two accounts paying 7% and 9% annual interest, respectively. If the total interest earned for the year was $600 how much was invested at each rate?

2 answers

if there is $x at 7%, the rest (8000-x) is at 9%. So, add up the interest:

.07x + .09(8000-x) = 600

Now just find x and 8000-x
566