You invest $75.00 the first month and $1,000.00 the second month at 3.75% APR. How much interest do you accrue at the end of the second month? (1 point) Responses $0.23 $0.23 $3.36 $3.36 $3.59 $3.59 $3.13

1 answer

To calculate the interest accrued at the end of the second month on the amounts you invested, you can use the formula for simple interest:

\[ \text{Interest} = P \times r \times t \]

Where:

  • \( P \) = principal amount (the amount of money invested)
  • \( r \) = annual interest rate (as a decimal)
  • \( t \) = time in years
  1. First Month Investment:

    • \( P_1 = 75.00 \)
    • \( r = 3.75% = 0.0375 \)
    • For the first month, \( t_1 = \frac{1}{12} \) years

    \[ \text{Interest for first month} = 75.00 \times 0.0375 \times \frac{1}{12} \]

    \[ \text{Interest for first month} = 75.00 \times 0.0375 \times 0.0833 = 0.234375 \]

  2. Second Month Investment (including the first month's interest):

    • First, calculate the interest on the first month's investment for the second month:

    \[ \text{Interest for second month on first investment} = 75.00 \times 0.0375 \times \frac{1}{12} \quad (\text{same as above}) \]

    \[ \text{Interest for second month on first investment} = 0.234375 \]

    • Now calculate the interest on the second month investment:

    • \( P_2 = 1000.00 \)

    • For the second month, \( t_2 = \frac{1}{12} \) years

    \[ \text{Interest for second month on second investment} = 1000.00 \times 0.0375 \times \frac{1}{12} \]

    \[ \text{Interest for second month on second investment} = 1000.00 \times 0.0375 \times 0.0833 = 3.125 \]

  3. Total Interest at the end of the second month:

    \[ \text{Total interest} = \text{Interest from first month} + \text{Interest from second month on first} + \text{Interest from second month on second} \]

    \[ \text{Total interest} = 0.234375 + 0.234375 + 3.125 \approx 3.59375 \]

Thus, rounding this calculation to two decimal points gives approximately $3.59.

The correct response from the options given is $3.59.