You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a reasonable approximation for the binomial distribution in this case.
While it is an uncommon confidence level, find the critical value that corresponds to a confidence level of 94.8%.
(Report answer accurate to three decimal places with appropriate rounding.)
z/2 = ±
1 answer
If you are looking for the Z score, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (±.474) to get its Z score.(1.95)