What is the total magnetic flux through the outer solenoid?
The total magnetic flux through the outer solenoid is equal to the product of the number of windings, Nouter, and the magnetic flux density, B, of the outer solenoid.
B = μ0 * Ninner * Iinner / (2 * π * Router)
Therefore, the total magnetic flux through the outer solenoid is:
Flux = Nouter * B = 2000 * μ0 * Ninner * Iinner / (2 * π * Router) = 2000 * μ0 * 170 * Iinner / (2 * π * 50)
You have two cylindrical solenoids, one inside the other, with the two cylinders concentric. The outer solenoid has length â„“outer = 400 mm, radius Router = 50 mm, and Nouter = 2000 windings. The inner solenoid has length â„“inner = 40 mm, radius Rinner = 20 mm, and Ninner = 170 windings. The inner solenoid is centered within the outer solenoid.
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