you have to solve the following by finding the value of x and y. can u help please?
x+3(x+1)=2x
1+3(x-1)=4
2x-2(x+1)=5x
2(3x-1)=3(x-1)
4(y-1)+3(y+2)=5(y-4)
3y+7+3(y-1)=2(2y+6)
These are exercises in standard algebraic manipulation of equations. Basically, you (1) multiply out terms in parentheses; (2) combine "like" terms and (3) then add to, subtract from, multiply or divide both sides of the equation until you get the unknown (x or y) on one side. Here is one way to do the first of them:
x+3(x+1)=2x
(Multiply out the parentheses)
x + 3x + 3 = 2x
(Combine terms in x)
4x + 3 = 2x
(Subract 2x +3 from both sides)
2x = -3
(Divide both sides by 2)
x = -3/2
Now you try the others. If cannot follow these steps, you should consider a private tutor before you fall too far behind in class.
thanx
1 answer