You have sampled a population in which you know that the percentage of the homozygous dominant genotype (AA) is 16%.

Question

Using that 16%, calculate the following - the frequency of the "A" allele. (p)



p2 + 2pq + q2 = 1 and p + q = 1
a
0.16
b
0.4
c
1
d
0.36

Answer 1

Let's define the variables as follows:
- p = frequency of the A allele
- q = frequency of the a allele

Given that the percentage of the homozygous dominant genotype (AA) is 16%, we know that p2 = 0.16. Since p2 represents the frequency of the homozygous dominant genotype, p would be the square root of 0.16.

p = √0.16
p = 0.4

Therefore, the frequency of the "A" allele (p) is 0.4.

So, the correct answer is:

b. 0.4