To calculate the frequency of the "a" allele, we can use the equation p + q = 1, where p is the frequency of the dominant allele and q is the frequency of the recessive allele.
Given that the frequency of the homozygous recessive genotype (aa) is 36%, we know that q^2 = 0.36. Therefore, q = √0.36 = 0.6.
So, the frequency of the "a" allele (q) is 0.6.
Therefore, the correct answer is:
c) 0.6
You have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%.
Using that 36%, calculate the following- the frequency of the "a" allele. (q)
p2 + 2pq + q2 = 1 and p + q = 1
a 0.36
b 0.4
c 0.6
d 1
choose the correct answer
1 answer