You have found that 14.37mL of 0.162M sulfuric acid reacts with exactly 20.00mL of barium hydroxide solution of unknown concentration. What is the molarity of the barium hydroxide solution? Round your answer to 3 decimal places and include units.

Question

I know that this has something to do with Molarity and that the molarity equation is (M) = moles of solute / volume of solution (in liters) What I'm unsure of is how do set it up wit the unknown?

Answer 1

That's right. M = mols/L or mols = M x L = ?
Four steps.
1. Write and balance the equation.
Ba(OH)2 + H2SO4 ==> BaSO4 + 2H2O

2. Convert what you have to mols.
mols Ba(OH)2 = M x L = ?

3. Using the coefficients in the balanced equation, convert mols Ba(OH)2 to mols H2SO4. The coefficients are 1:1 therefore, mols Ba(OH)2 = mols H2SO4.

4. Then M H2SO4 = mols H2SO4/L H2SO4 = ?