Actually, there isn't enough information to answer the question. The below will calculate the volume of NaOH required to reach the EQUIVALENCE POINT (which I assume is what the problem wants). The problem asks, however, mL required to read the END POINT. The end point depends upon the indicator being used and that isn't given in the problem. I would be one value if methyl orange is used, another if methyl red is used, and another if phenolphthalein is used.
Since vinegar is a monoprotic acid and NaOH is monobasic, the ratio is 1:1; therefore, 1 mol acid will be neutralized by 1 mol of the base.
mLacid x M acid = mL base x M base.
Substitute and solve for volume NaOH
You have a vinegar solution you believe to be 0.8 M. You are going to titrate 21.39 mL of it with a NaOH solution that you know to be 0.774 M. At what volume of added NaOH solution would you expect to see an end point? Answer in units of mL
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Thank You!! I got it right! My answer is 22.10853.
That's a lot of significant figures you are quoting.
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