pens--- x
pencils --y
x+y = 21
x = y+3
I just translated the English to Math
solve
You have a total of 21 pens and pencils. You have 3 more pens than pencils. Write a system of linear equations that represent this situation. How many of each do you have?
2 answers
Let p = number of pencils
Therefore pens = p + 3
P + (p+3) = 21
2p + 3 = 21
Then solve for p
Therefore pens = p + 3
P + (p+3) = 21
2p + 3 = 21
Then solve for p