You need 3*1.6 = 4.8 mols of stuff
it is 8 mols/liter
4.8 mols ( 1 liter/8 mols) = .6 liters of the strong stuff
so mix 0.6 liters of the 8 M stuff with 1 liter of water
You have a large amount of 8.00 M stock solution. You need 1.60 L of 3.00 M solution for an experiment. How would you prepare the desired solution without wasting any stock solution?
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