You have a bucket with 3 black balls and 7 red balls. What is the probability of drawing 2 reds and 1 black in 3 draws if order is not important? (Assume replacement after each draw)

Answer 1

ways to do this:
RRB
RBR
BRR

so three ways, then Pr= 3*7/10*7/10*3/10

Answer 2

So Bob - Final answer would be .441?