you have a 0.200L of solution containing 250mM phosphate buffer, pH 6.8.
An equivalent amount of HCl/NaOH with respect to the total amount of phosphate in the buffer --> mmol of NaH2PO3 + mmol of NaH2PO4 = 50 mmoles.
What would the pH of the above buffer solution be after you add the following with respect to the total amount of phosphate in the buffer:
1) 1/8 equivalent amount of NaOH
2) 1/8 equivalent amount of HCl
Please explain. I'm not really looking for an answer but how it works.
Thank you
2 answers
for 1) I got 7.42 after trying. I wanted to confirm if it is right to see if I got the process right?
I have no idea what this question means. My best suggestion is that if you understand the question that you use the same kind of process I used for that phosphate buffer I did last night.
2 answers