You have 5 liters of Solution A, which is 50% diluted, and 15 liters of Solution B, which is 20% diluted. How much of Solution B must be added to Solution A to make Solution A 55% diluted?(1 point)

Question

Responses

105 liters
105 liters

0.71 liters
0.71 liters

−105
liters
negative 105 liters

The answer is extraneous.

Answer 1

To solve this problem, we can set up an equation based on the information given.

Let x represent the amount of Solution B (in liters) that needs to be added to Solution A.

The total volume of the resulting solution after adding Solution B is 5 + x liters.

The total amount of diluted substance in the resulting solution is 0.55*(5 + x) liters.

The total amount of diluted substance in Solution A is 0.5*5 = 2.5 liters.

The total amount of diluted substance in Solution B is 0.2*15 = 3 liters.

Setting up the equation:
2.5 + 3 = 0.55*(5 + x)

Simplifying the equation:
5.5 = 2.75 + 0.55x

Subtracting 2.75 from both sides:
2.75 = 0.55x

Dividing both sides by 0.55:
5 = x

Therefore, we need to add 5 liters of Solution B to Solution A to make Solution A 55% diluted.