Perimater=4L=2width+1length
or length=4L-2w
area=width(4L-2W)
darea/dw=(4L-2w) + w(-2)=0
width=L
length=2L
check my thinking
You have 4L feet of fence to make a rectangular vegetable garden alongside the wall of your house, where L is a positive constant. The wall of the house bounds one side of the vegetable garden. What is the largest possible area for the vegetable garden?
3 answers
looks correct. The fence is divided equally among lengths and widths.
yes 2L^2 is correct