if the width is w, then the length is 200-w. (why?)
the area is w(200-w).
Can you take it from there?
You have 400 feet of fencing to enclose a rectangular plot. Find the length and width of the plot that will maximize the area. What is the largest area that can be enclosed?
I'm not sure how to start. We haven't learned this yet in class.
2 answers
A=Lw
P=2L+2w
400=2L+2w
400-2L=2w
-2L=-400+2w
L=200-w
A=(200-w)(w)
A=200w-w^2
A=-w^2+200
-b
----- =
2a
-200
-------=
2(-1)
-200
------- =
-2
100
Y=400-100
Y=300
So the. Would the length for each side of the rectangle be 50 and the width be 150?
P=2L+2w
400=2L+2w
400-2L=2w
-2L=-400+2w
L=200-w
A=(200-w)(w)
A=200w-w^2
A=-w^2+200
-b
----- =
2a
-200
-------=
2(-1)
-200
------- =
-2
100
Y=400-100
Y=300
So the. Would the length for each side of the rectangle be 50 and the width be 150?
1 answer