You have 3.00 L of a 2.37 M solution of NaCl(aq) called solution A. You also have 2.00 L of a 2.00 M solution of AgNO3(aq) called solution B. You mix these solutions together, making solution C.

Question

Calculate the concentration (in M) of Na+ ions in solution C.

Answer 1

The sodium ion is a spectator ion in this reaction, i.e. it does not take part. Thus we can ignore the chemistry.

Number of moles at start

3.00 L x 2.37 mole L^-1

Because 1 mole of NaCl gives 1 mole of Na+ in solution.

volume at end = 3.00 L + 2.00 L
=5.00 L

so concentration of Na+ at end is
moles/volume
=3.00 L x 2.37 mole L^-1/5.00 L

Answer 2

1.162