a + b + c + d + e = 100
a + b = 30
b + c = 36
c + d = 49
d + e = 47
a = 30 - b
c = 36 - b
d = 49 - c = 49 - (36 - b) = 13 + b
e = 47 - d = 47 - (49 - c) = c - 2 = (36 - b) - 2 = 34 - b
(30 - b) + b + (36 - b) + (13 + b) + (34 - b) = 100
113 - b = 100
b = 13
Therefore,
Bowl A = 30 - 13 = 17
Bowl B = 13
Bowl C = 36 - 13 = 23
Bowl D = 13 + 13 = 26
Bowl E = 34 - 13 = 21
You have 100 pieces of candy in five bowls. The sum of candy in bowl a and bowl b is 30 pieces. The sum of candy in bowl b and c is 36 pieces. The sum of candy in bowl c and bowl d is 49 pieces of candy. The sum of bowl d and bowl e is 47 pieces of candy. How many pieces of candy are in each bowl?
1 answer
1 answer