You find out you need a pallet of 14 bags of seed that weigh 50 lbs each. You know the pallet itslef weighs 44lbs. The CO-OP forklift takes 30 seconds to move the pallet and bags of seed the 60 feet to the back of your truck.

Question

A) How much power does the forklift produce to move the bags and pallet?

B) How much horsepower is needed to move the bags and pallet?

C) If the forklift were to break, how long would it take you and the CO-OP worker to move JUST

power= work/time= mgh/time

I will be happy to critique your work.

what does the mgh stand for?
on part a. i got
p=744lbs/30sec
=24.8lbs/sec but that's not the right answer....where did i go wrong?

Matt

Formula:

W = Fd kg m/s2 meters Work equals force times distance,

F = ma kg m/s2 Force equals mass times acceleration,

a = g m/s2 Acceleration is g,

F = mg kg m/s2 So force equals mass times g,

W = mgd kg m/s2 meters Which means work equals mass times g times distance,

d = h meters Distance equals height,

W = mgh kg m/s2 meters Which makes work equal to mass times g times height,

W=PE Which means potential energy it the amount of work an object could do.

mgh = (mass*gravity*height)

i think i got it
w=744*60=44,640ft-lbs

p=44,640ft-lbs/30sec
=1488ft-lbs/sec

see my post. If the 60 feet were up in the air. I read the 60 feet as horizontal. No work is done, ignoring friction.

mgh is the weight*height.

Now there is a problem with the problem. No power is used if the bags are not lifted. Just moving the bags requires no power, IF one ignores friction.
In real life, friction is considerable for a forklift, and the problem does not give any indication of that (like coefficent of friction on wheels). It did take power to lift the bags, but that is not asked in the questions.

i undertand but i guess he thinks we just assume.