You exert a force of 200 N at an angle of 15 degrees above horizontal to pull a 10 kg box across the floor at constant velocity. If the coefficient of kinetic friction between the box and the floor is 0.42, what is the acceleration of the box?

Answer 1

some of the force is reducing weight W.

net force=mass*acceleration
200cos15-mu*W=m*acceleration
200cos15-mu*(mg-200sin15)=m*a
solve for acceleration a.