You drive a car 1500 ft to the east, then 2500 ft to the north. If

the trip took 3.0 minutes, what were the direction and magni￾tude of your average velocity?

2 answers

final displacement: d = 500√34
avg speed: d/3 ft/min
direction: tanθ = 2500/1500 = 5/3
direction of average velocity is 59 north of east
and magnitude of average velocity is 4.2 m/s