Trig: horizontal distance=62
vertical distance=62*tan2
time to fall vertical distance...
h=1/2 g t^2
62*tan2=1/2 g t^2 solve for t.
speed= 62/t
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 62.0 m away, making a 2.00 degree angle with the ground.
How fast was the arrow shooting?
3 answers
i get 93, but my hw says its wrong
same question with different numbers cant get the answer don't think that's the right equation to use
1 answer