To solve this puzzle, we need to translate the clues into a system of equations. Let's denote the blue number as \( b \) and the red number as \( r \).
From Clue 1, we have:
- \( 2b + r = 6 \)
From Clue 2, we have:
- \( 4b + 2r = 12 \)
Let's simplify the second equation. We can divide the entire equation by 2:
\[ 2b + r = 6 \]
Now we have:
- \( 2b + r = 6 \) (Clue 1)
- \( 2b + r = 6 \) (Clue 2)
Notice that both equations are identical. This means that they represent the same line when graphed, and thus they have an infinite number of solutions along that line.
To express \( r \) in terms of \( b \) from either equation, we can rearrange Equation 1:
\[ r = 6 - 2b \]
We have expressed \( r \) in terms of \( b \), which indicates that for any value of \( b \), we can find a corresponding \( r \). For example, if \( b = 0 \), then \( r = 6 - 2 \cdot 0 = 6 \). If \( b = 1 \), then \( r = 6 - 2 \cdot 1 = 4\), and so on.
Thus, there are infinitely many pairs of \( (b, r) \) that satisfy the equations.
In conclusion: There are an infinite number of solutions to this puzzle based on the given clues.