You are trying to compare the Farenheit and Celcius scales and you have two examples; Temperatur A is 50 degrees Celcius and 122 Farenheit. Temperature B is 100 degrees Celcius and 212 degrees Farenheit. What graph models the relationship between Farengeit and Celcius scales? What is an equation of the line in slope intercept form.

Question

I know you cant see the graphs but maybe be able to explain a little.

Answer 1

I suggest the following:
draw a horizontal axis, called C , for Celsius
draw a vertical axis , called F for Fahrenheit, (note the correct spelling)

label one point as A(50, 122) and another B((100,212)
join with a straight line.
pick any point P(C,F)

slope of PA = slope BA
(F-122)/(C-50) = (212-122)/(100-50)
(F-122)/(C-50) = 90/50 = 9/5
cross-multiply
5F - 610 = 9C - 450
5F = 9C + 160

F = (9/5)C + 32 or re-arrange to get C = ....

Answer 2

I believe it would be y=9/5+32 if I made the graph right. Am I close?

Answer 3

Not understanding how to graph my answer

Answer 4

your right