For a,how much NaCl is needed?
100 mg/L is what you want, and you want 500 mL; therefore, you need 100 mg/L x 0.500 L = ? mg.
For b,
You want 500 mL of 5 mg/L; therefore, you need 5 mg/L x 0.5L = 2.5 mg P.
You have 100 mg/L solution, how much of that do you need?
100 mg/L x ?L = 2.5
Solve for L and convert to mL. I'll leave c for you. Same process but you must find NO3^- and add Na from that to Na from NaCl. Find total Na and final volume is 500 mL.
You are tasked with preparing a 500mL nutrient solution containing 5mg/L of phosphorous
(P), 3mg/L nitrate (NO3
-) and 100 mg/L chloride (Cl-). To make this solution, you have
powdered sodium chloride, a 100 mg/L solution of phosphorus, a 1000 mg/L of sodium nitrate
(NaNO3) and water. Based on the final solution:
a. How many milligrams of sodium chloride is required?
b. What volume (in mL) of the 100 mg/L phosphorus solution is required?
c. What is the final concentration of sodium?
Any help is appreciated. Thank you!
2 answers
Thank you for your help!
For part c, I'm not sure what you mean finding Na from NO3^-?
For part c, I'm not sure what you mean finding Na from NO3^-?