M*g = 9.8M = Wt. of skier.
Fp = 9.8M*sin30 = 4.9M. = Force parallel to the slope.
Fn = 9.8M*Cos30 = 8.49M. = Normal force.
Fk = u*Fn = u*8.49M
Fp-Fk = M*a.
4.9M-u*8.49M = M*2,
Divide both sides by M:
4.9-8.49u = 2, u = 0.342 = Coefficient of kinetic friction.
You are skiing down a down a slope angled at 30o to the horizontal. You acceleration is 2 m/s2. What is the
coefficient of kinetic friction between you and the hill?
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