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You are rolling a number cube to help you pick the number of minutes you will run in each of your workout sets. Determine the p...Question
You are rolling a number cube to help you pick the number of minutes you will run in each of your workout sets. Determine the probability of rolling an odd number three times in a row.(1 point) Responses 1216 Start Fraction 1 over 216 End Fraction 18 Start Fraction 1 over 8 End Fraction 32 Start Fraction 3 over 2 End Fraction 12
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GPT-4o mini
To determine the probability of rolling an odd number three times in a row on a standard number cube (a six-sided die), we first identify the odd numbers on the die. The odd numbers on a number cube (1 to 6) are 1, 3, and 5.
There are a total of 3 odd numbers out of 6 possible outcomes. Thus, the probability of rolling an odd number in one roll is:
\[
P(\text{odd}) = \frac{3}{6} = \frac{1}{2}
\]
Now, to find the probability of rolling an odd number three times in a row, we use the multiplication rule of probability, since the rolls are independent events:
\[
P(\text{odd three times}) = P(\text{odd}) \times P(\text{odd}) \times P(\text{odd}) = \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}
\]
Thus, the probability of rolling an odd number three times in a row is:
\[
\frac{1}{8}
\]
So the correct answer is:
\[
\text{Start Fraction 1 over 8 End Fraction}
\]
There are a total of 3 odd numbers out of 6 possible outcomes. Thus, the probability of rolling an odd number in one roll is:
\[
P(\text{odd}) = \frac{3}{6} = \frac{1}{2}
\]
Now, to find the probability of rolling an odd number three times in a row, we use the multiplication rule of probability, since the rolls are independent events:
\[
P(\text{odd three times}) = P(\text{odd}) \times P(\text{odd}) \times P(\text{odd}) = \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) \times \left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}
\]
Thus, the probability of rolling an odd number three times in a row is:
\[
\frac{1}{8}
\]
So the correct answer is:
\[
\text{Start Fraction 1 over 8 End Fraction}
\]
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