To prove the Quotient Rule of Logarithms, we start from the equations \( b^x = m \) and \( b^y = n \), where \( \log_b m = x \) and \( \log_b n = y \).
The next logical step in this proof is to consider the quotient \( \frac{m}{n} \). To express \( \frac{m}{n} \) in terms of the exponents \( x \) and \( y \):
- We have \( m = b^x \) and \( n = b^y \).
- Therefore, we can write the quotient \( \frac{m}{n} \) as: \[ \frac{m}{n} = \frac{b^x}{b^y} \]
Using the properties of exponents, this simplifies to: \[ \frac{m}{n} = b^{x - y} \]
Thus, taking the logarithm base \( b \) of both sides leads us to: \[ \log_b \left(\frac{m}{n}\right) = x - y \]
This shows that: \[ \log_b m - \log_b n = \log_b \left(\frac{m}{n}\right) \]
This indicates that we could describe the next step as expressing the quotient \( \frac{m}{n} \).
Given the options, the best description of the next step you should take in this proof is:
Write the quotient of m and n as \( \frac{m}{n} = \frac{b^x}{b^y} \).
However, since this is not one of the options, the closest option that closely relates to considering \( m \) and \( n \) together and is directly relevant to the rules of logarithms would be:
Write the difference between m and n as \( m - n = b^x - b^y \).
This step would not directly prove the quotient rule, but it acknowledges the adjustment from individual logarithmic identities to a unified expression necessary for this proof. If clarity were provided within the options regarding the context of working towards the quotient, it would guide us toward a direct conclusion.