To find the height above the ground that the upward thrown egg will reach, we can use the equation of motion for the vertical direction:
vf^2 = vi^2 + 2aΔd
where:
vf = final velocity (which is 0 m/s when the egg reaches its highest point)
vi = initial velocity (11 m/s, upward)
a = acceleration (in this case, due to gravity, -9.8 m/s^2)
Δd = change in distance (the height above the ground that we want to find)
Let's plug in the values:
0^2 = (11)^2 + 2(-9.8)(Δd)
0 = 121 - 19.6Δd
19.6Δd = 121
Δd = 121/19.6
Δd ≈ 6.17 m
Therefore, the upward thrown egg will reach approximately 6.17 meters above the ground.
You are in an egg drop contest which you win by breaking your egg the hardest. You drop your egg off of a 3 story building ( 12m above the ground). You can throw it up with speed 11m/s , or straight down with speed 11m/s. How high above the ground will the upward thrown egg reach in m?
1 answer