d = 3.6 + 0.5 = 4.1 miles.
T1 = 3.6/9 + 12/60 = 0.6 hr. To travel
4.1 miles from starting point.
V1 = d/T1 = 4.1/0.6 = 6.83 mi/h.
V2=9.0 mi/h. when returning to starting
point.
V = (V1+V2)/2 = (6.83+9.0)/2 = 7.92 mi/h
= Average velocity for entire trip.
You are going for a bike ride. You ride down a straight road at a speed of 9.0 mi/hr. Just as you pass the point which is 3.6 miles from your starting point, you develop a flat tire. You get off your bike and walk it to a bike shop 0.5 miles further down the road. The walk to the bike shop takes 12 minutes. What was the average velocity for the entire trip?
1 answer
3 answers