You are given the following data.

P4(s) + 6 Cl2(g) 4 PCl3(g) ΔH = -1225.6 kJ
P4(s) + 5 O2(g) P4O10(s) ΔH = -2967.3 kJ
PCl3(g) + Cl2(g) PCl5(g) ΔH = -84.2 kJ
PCl3(g) + 1/2 O2(g) Cl3PO(g) ΔH = -285.7 kJ
Calculate ΔH for the following reaction.

P4O10(s) + 6 PCl5(g) 10 Cl3PO(g)

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