you are given a solid that is a mixture of na2s04 and k2s04. A0.215g sample of the mixture is dissolved in water. An excess of an aqueous solution of bacl2 is added. The bas04 that is formed is filtered dried and weight. Its mass is 0.299g what mass of s04 ions is the sample
My calculation 0.299g/233.4g/mol = 0.00128
0.00128 x 96g/mol = 0.123g s04
What is the mass percent of s04 ion in the sample
0.123g/0.215 x 100 = 57.2%
what are the percent composition by mass of na2s04 and k2s04
x/142 = y/174 = 0.00128
Who helps me to solve this part