First go back and see my change to the earlier problem I did percent of moles and it should be percent of grams. You had the correct answer, 60%
I can not do another one right now.
you are given a solid that is a mixture of na2s04 and k2s04. A 0.215g sample of the mixture is dissolved in water. An excess of an aqueous solution of bacl2 is added. The bas04 that is formed is filtered, dried and weighed. Its mass is 0.299g. What mass of s04 ion is in the sample
My calculation 0.299/233g/mol = 0.00128 x 96 g/mol = 0.123g
What is the mass percent of s04 in the sample 0.213g/ 0.215g x 100 = 57.2%
what are the percent composition by mass of na2s04 and k2s04 in the sample
I cannot solve this part
na2s04 16.9%
k2s04 83.1%
Damon step by step for me Thank you a lot
3 answers
Hey, this looks just like the last problem with new numbers. If you learn how to do the last one, you can do this one.
I agree with Damon. Look how I did NaCl and KCl mixture above.