23.0 what Al? grams?
28.0 what Cl? grams?
2Al + 3Cl2 ==> 2AlCl3
mols Al = 23.0/atomic mass Al = ?
mols AlCl3 = the same (look at the coefficients).
You are given 23.0 of aluminum and 28.0 of chlorine gas.
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 23.0 of aluminum?
Express your answer to three significant figures and include the appropriate units.
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