Let's denote the price of the chicken tender Pub sub as \( x \) and the price of the deli ultimate Pub sub as \( y \).
From the information provided, we can set up the following equations based on the purchases:
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For the first lunch purchase: \[ 6x + 6y = 30 \] We can simplify this equation by dividing everything by 6: \[ x + y = 5 \quad \text{(Equation 1)} \]
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For the later night purchase: \[ 4x + 8y = 30.60 \] We can simplify this equation by dividing everything by 4: \[ x + 2y = 7.65 \quad \text{(Equation 2)} \]
Now we have a system of equations: \[ \begin{align*}
- & \quad x + y = 5 \
- & \quad x + 2y = 7.65 \end{align*} \]
Next, we'll solve these equations. We can express \( y \) from Equation 1: \[ y = 5 - x \]
Now we can substitute this expression for \( y \) into Equation 2: \[ x + 2(5 - x) = 7.65 \]
Distributing the 2: \[ x + 10 - 2x = 7.65 \]
This simplifies to: \[ 10 - x = 7.65 \]
Now, solving for \( x \): \[ -x = 7.65 - 10 \] \[ -x = -2.35 \] \[ x = 2.35 \]
Now that we have the price of the chicken tender Pub sub, we can find \( y \): \[ y = 5 - x = 5 - 2.35 = 2.65 \]
Thus, the prices of the Pub subs are:
- Chicken tender Pub sub: \( \boxed{2.35} \)
- Deli ultimate Pub sub: \( \boxed{2.65} \)