NH3 + HOH ==> NH4^+ + OH^-
Kb = (NH4^+)(OH^-)/(NH3)
Convert pH to OH^-, substitute into Kb and solve for NH3 (in mols/L).
Convert to mols (M x L), convert that to grams NH3 and from there use density and solve for cc and convert to L. Post your work if you get stuck.
You are farming and loving life. You love the smell of ammonia and apply it to your field as a fertilizer. However, you have a pond which you use to water your crops and for your llamas drinking water. The ammonia you spread on your field washes into the pond (it has a volume of 3.0 x 10^6 L of water). When you test the pond water is has a pH of 9.81. How much liquid ammonia from your fertilizing made its way into the pond? Give your answer in L of ammonia.
Given: Kb(NH3) = 1.8 x 10^-5; the density of liquid ammonia is 0.771 g/cm^3
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