To find the length of the log, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height (or length) of the cylinder.
From the problem, we know:
- The volume \( V = 10,000\pi \) in³.
- The diameter of the log is 32 inches, so the radius \( r \) is half of that:
\[ r = \frac{32}{2} = 16 \text{ inches} \]
Now we can substitute these values into the volume formula:
\[ 10,000\pi = \pi (16)^2 h \]
First, we calculate \( (16)^2 \):
\[ 16^2 = 256 \]
Now the equation becomes:
\[ 10,000\pi = \pi (256) h \]
We can divide both sides by \( \pi \) (since it is non-zero):
\[ 10,000 = 256h \]
To find the height \( h \), we divide both sides by 256:
\[ h = \frac{10,000}{256} \]
Calculating the right-hand side:
\[ h = 39.0625 \]
Rounding to the nearest hundredth, the length of the log is:
\[ \boxed{39.06} \text{ inches} \]