3.8 L=3.8x10^-3 m^3
D=1 g/mm^3 =1000 kg/m^3
m=DxV=1000 x 3.8x10^-3=3.8 kg
You are carrying a 3.4 gallon jug full of cold water. Given that the water has a density of 1.0 grams per milliliter, and one gallon is equal to 3.8 liters, state the mass of the water in kilograms.
1 answer
1 answer