You are camping out and wish to bake an apple crisp using your Butane cooker. The crisp needs 1.5x10^3 kJ of heat per kg to completely cook and the combustion of butane (C4H10) gas produces 2877.3 kj of thermal energy. Your cooker contains 100.0 g of butane. How much apple crisp can you cook (in lbs) if 80% of the energy from the reaction is lost to the great outdoors?

Answer 1

First, let's calculate the amount of thermal energy produced by the butane gas in the cooker:
100.0 g of butane = 0.1 kg of butane
Thermal energy produced = 0.1 kg × 2877.3 kJ = 287.73 kJ

Next, let's calculate the amount of thermal energy available for cooking:
Energy lost to the great outdoors = 80% of 287.73 kJ = 0.8 × 287.73 kJ = 230.18 kJ

Now, let's calculate the amount of apple crisp that can be cooked with this thermal energy:
Heat required for cooking 1 kg of apple crisp = 1.5 × 10^3 kJ/kg
Amount of apple crisp cooked = Energy available for cooking / Heat required per kg
= 230.18 kJ / (1.5 × 10^3 kJ/kg) = 0.153 kg

Finally, let's convert the amount of apple crisp from kg to pounds:
1 kg = 2.20462 lbs
0.153 kg = 0.153 × 2.20462 lbs = 0.337 lbs

Therefore, you can cook approximately 0.337 pounds of apple crisp using your Butane cooker.