You are a workstudy for the chemistry department. Your supervisor has just asked you to prepare 500mL of 3M HCl for tomorrow's undergraduate experiment. In the stockroom explorer, you will find a cabinet called "Stock Solutions". Open this cabinet to find a 2.0L bottle labeled "11.6M HCl". The concentration of the HCl is 11.6M. Please prepare a flask containing 500 ml of a 3 M (+/- 0.005M) solution and relabel it with its precise molarity. Note that you must use realistic transfer mode, a buret, and a volumetric flask for this problem.
As a reminder, to calculate the volume needed to make a solution of a given molarity, you may use the following formula:
C1V1 = C2V2
C[mol/l], v[mL]
C[mol/l] X v/1000 [L] = CV/1000 [mol]
11.6M HCI c2=3M V2= 500 mL
C1=11.6 M V1(mL)
the answer is Volume of HCl used 500ml
7 answers
129.31 ml
22.5 ml?
500mL of 3M HCl contains 1.5 moles of HCl
so 129.31 mL of the 11.6 M acid is needed
acid is added to water (NOT vice versa)
using a volumetric cylinder, add the necessary acid to 350 ml of water
... then add more water to make the 500 mL of solution required
so 129.31 mL of the 11.6 M acid is needed
acid is added to water (NOT vice versa)
using a volumetric cylinder, add the necessary acid to 350 ml of water
... then add more water to make the 500 mL of solution required
2.25
use the following formula:
C1V1 = C2V2
11.6M HCI
c2=3M
V2= 500 mL
v1=129.31
C1=11.6 M V1(mL)
C1V1 = C2V2
11.6M HCI
c2=3M
V2= 500 mL
v1=129.31
C1=11.6 M V1(mL)
the answer is 2.25 ml
what is the percentage error % error = (experimental concentration – 3.0 M) / 3.0 M * 100, in absolute value.
one of the people answered and said it is 129.31 ml is that the correct answer
one of the people answered and said it is 129.31 ml is that the correct answer