To find the total weight of the suitcases, we first need to convert all weights to improper fractions and then sum them up.
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Convert the weights of the suitcases:
- \( 24 \frac{1}{2} = 24 + \frac{1}{2} = \frac{48}{2} + \frac{1}{2} = \frac{49}{2} \)
- \( 13 \frac{3}{8} = 13 + \frac{3}{8} = \frac{104}{8} + \frac{3}{8} = \frac{107}{8} \)
- \( 3 \frac{1}{2} = 3 + \frac{1}{2} = \frac{6}{2} + \frac{1}{2} = \frac{7}{2} \)
- \( 17 \frac{3}{4} = 17 + \frac{3}{4} = \frac{68}{4} + \frac{3}{4} = \frac{71}{4} \)
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Convert all fractions to have a common denominator. The least common multiple of 2, 8, and 4 is 8. We convert each weight:
- \( \frac{49}{2} = \frac{49 \times 4}{2 \times 4} = \frac{196}{8} \)
- \( \frac{107}{8} \) stays the same.
- \( \frac{7}{2} = \frac{7 \times 4}{2 \times 4} = \frac{28}{8} \)
- \( \frac{71}{4} = \frac{71 \times 2}{4 \times 2} = \frac{142}{8} \)
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Sum the weights:
- Total weight = \( \frac{196}{8} + \frac{107}{8} + \frac{28}{8} + \frac{142}{8} \)
- Combine the numerators: \[ 196 + 107 + 28 + 142 = 473 \]
- So, the total weight is: \[ \frac{473}{8} \]
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Convert to a mixed number if needed: \(\frac{473}{8}\) can be converted to a mixed number:
- Divide \(473\) by \(8\):
- \(8\) goes into \(473\) 59 times (since \(8 \times 59 = 472\)) with a remainder of \(1\).
- So, \( \frac{473}{8} = 59 \frac{1}{8}\).
- Divide \(473\) by \(8\):
The total weight of all the luggage is 59 1/8 ib, which corresponds to the improper fraction of \( \frac{473}{8} ib \).
Looking at your choices, the correct equivalent fraction for \(59 \frac{1}{8}\) is:
- 588/8 ib, (which is \( \frac{473}{8} \)).
The final total weight of all the luggage is therefore:
588/8 ib.