To find the total weight of the suitcases, we need to add up all of their individual weights.
Let's write down the weights:
- \( 24 \frac{1}{2} \) lb
- \( 13 \frac{3}{8} \) lb
- \( 3 \frac{1}{2} \) lb
- \( 17 \frac{3}{4} \) lb
Before adding, it can be easier to convert all mixed numbers to improper fractions.
Step 1: Convert mixed numbers to improper fractions
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\( 24 \frac{1}{2} = 24 + \frac{1}{2} = \frac{49}{2} \)
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\( 13 \frac{3}{8} = 13 + \frac{3}{8} = \frac{107}{8} \)
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\( 3 \frac{1}{2} = 3 + \frac{1}{2} = \frac{7}{2} \)
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\( 17 \frac{3}{4} = 17 + \frac{3}{4} = \frac{71}{4} \)
Step 2: Find a common denominator
The denominators are 2, 8, and 4. The least common multiple (LCM) of these denominators is 8.
Now we’ll convert each of the improper fractions to have a denominator of 8:
-
\( \frac{49}{2} = \frac{49 \times 4}{2 \times 4} = \frac{196}{8} \)
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\( \frac{107}{8} = \frac{107}{8} \) (stays the same)
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\( \frac{7}{2} = \frac{7 \times 4}{2 \times 4} = \frac{28}{8} \)
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\( \frac{71}{4} = \frac{71 \times 2}{4 \times 2} = \frac{142}{8} \)
Step 3: Add the fractions
Now we can add all these fractions together: \[ \frac{196}{8} + \frac{107}{8} + \frac{28}{8} + \frac{142}{8} = \frac{196 + 107 + 28 + 142}{8} \]
Calculating the numerator: \[ 196 + 107 = 303 \] \[ 303 + 28 = 331 \] \[ 331 + 142 = 473 \]
Thus, we have: \[ \frac{473}{8} \]
Step 4: Convert the improper fraction back to a mixed number
To convert \( \frac{473}{8} \) to a mixed number:
- Divide 473 by 8:
- \( 473 \div 8 = 59 \) remainder \( 1 \)
Thus, we have: \[ \frac{473}{8} = 59 \frac{1}{8} \]
Final conversion to decimal
Now, since \( 59 \frac{1}{8} = 59 + 0.125 \), we convert to a decimal: \[ 59 + 0.125 = 59.125 \]
Compare with the answers
The choices given in the problem are:
- A. \( \frac{588}{8} \) (which corresponds to 73.5)
- B. \( 69 \frac{3}{8} \) (which is 69.375)
- C. \( 85 \frac{1}{8} \) (which is 85.125)
- D. \( 71 \frac{1}{8} \) (which is 71.125)
Since: \[ \frac{473}{8} = 59 \frac{1}{8} = 59.125 \]
None of the answers match 59.125, indicating a possible error in the original set of choices or weights provided. The calculation appears correct, so the correct answer is:
\( 59 \frac{1}{8} \) lb or \( \frac{473}{8} \) (which is not in the provided options).