Asked by Elena

You and 4 friends go to a concert. In how many different ways can you sit in the assigned seats?
20
24
48
120
I think its A im not to sure
Answered by oobleck
5 people, so
1st seat: 5 choices
2nd seat: 4 choices
...
for a total of 5*4*3*2*1 = 120 ways to sit
Answered by BabyJesus
that answer is so wrong.
Answered by (o-o)
so
what is the answer?
Answered by connexus kid
The answer is 24

There are 24 possible permutations for these 4 items.
For n items, there are n! (n factorial) ways of arranging them, when the order of your arrangements matters.
n!=n × (n-1) × (n-2) × ... 1. Here 4!=4 × 3 × 2 × 1 = 24.

Here are the possible permutations:

1: 1 2 3 4
2: 1 2 4 3
3: 1 3 2 4
4: 1 4 2 3
5: 1 3 4 2
6: 1 4 3 2
7: 2 1 3 4
8: 2 1 4 3
9: 3 1 2 4
10: 4 1 2 3
11: 3 1 4 2
12: 4 1 3 2
13: 2 3 1 4
14: 2 4 1 3
15: 3 2 1 4
16: 4 2 1 3
17: 3 4 1 2
18: 4 3 1 2
19: 2 3 4 1
20: 2 4 3 1
21: 3 2 4 1
22: 4 2 3 1
23: 3 4 2 1
24: 4 3 2 1
Answered by TYTYM
it is 120

you (1) AND 4 friends

what is 1+4
5

what is 5! (5*4*3*2*1)
120
Answered by He got a point.
Math has been known for its trickery. I believe that you are included as a fifth friend. So I believe it is 120.
Answered by memes...
You and 4 friends go to a concert. In how many different ways can you sit in the assigned seats?

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