5 people, so
1st seat: 5 choices
2nd seat: 4 choices
...
for a total of 5*4*3*2*1 = 120 ways to sit
You and 4 friends go to a concert. In how many different ways can you sit in the assigned seats?
20
24
48
120
I think its A im not to sure
8 answers
that answer is so wrong.
so
what is the answer?
what is the answer?
The answer is 24
There are 24 possible permutations for these 4 items.
For n items, there are n! (n factorial) ways of arranging them, when the order of your arrangements matters.
n!=n × (n-1) × (n-2) × ... 1. Here 4!=4 × 3 × 2 × 1 = 24.
Here are the possible permutations:
1: 1 2 3 4
2: 1 2 4 3
3: 1 3 2 4
4: 1 4 2 3
5: 1 3 4 2
6: 1 4 3 2
7: 2 1 3 4
8: 2 1 4 3
9: 3 1 2 4
10: 4 1 2 3
11: 3 1 4 2
12: 4 1 3 2
13: 2 3 1 4
14: 2 4 1 3
15: 3 2 1 4
16: 4 2 1 3
17: 3 4 1 2
18: 4 3 1 2
19: 2 3 4 1
20: 2 4 3 1
21: 3 2 4 1
22: 4 2 3 1
23: 3 4 2 1
24: 4 3 2 1
There are 24 possible permutations for these 4 items.
For n items, there are n! (n factorial) ways of arranging them, when the order of your arrangements matters.
n!=n × (n-1) × (n-2) × ... 1. Here 4!=4 × 3 × 2 × 1 = 24.
Here are the possible permutations:
1: 1 2 3 4
2: 1 2 4 3
3: 1 3 2 4
4: 1 4 2 3
5: 1 3 4 2
6: 1 4 3 2
7: 2 1 3 4
8: 2 1 4 3
9: 3 1 2 4
10: 4 1 2 3
11: 3 1 4 2
12: 4 1 3 2
13: 2 3 1 4
14: 2 4 1 3
15: 3 2 1 4
16: 4 2 1 3
17: 3 4 1 2
18: 4 3 1 2
19: 2 3 4 1
20: 2 4 3 1
21: 3 2 4 1
22: 4 2 3 1
23: 3 4 2 1
24: 4 3 2 1
it is 120
you (1) AND 4 friends
what is 1+4
5
what is 5! (5*4*3*2*1)
120
you (1) AND 4 friends
what is 1+4
5
what is 5! (5*4*3*2*1)
120
Math has been known for its trickery. I believe that you are included as a fifth friend. So I believe it is 120.
You and 4 friends go to a concert. In how many different ways can you sit in the assigned seats?
bot?
bot?
This is a combinatorial problem. The number of ways you and 4 friends can sit in assigned seats can be calculated using permutations.
The answer is 120.
This can be calculated as follows:
There are 5 people in total, so the first seat can be filled by any of the 5 people.
Once the first seat is filled, there are only 4 people left that can fill the second seat.
After the second seat is filled, there are only 3 people left that can fill the third seat.
After the third seat is filled, there are only 2 people left that can fill the fourth seat.
Lastly, there is only 1 person left that can fill the fifth seat.
Therefore, the total number of ways you and 4 friends can sit in assigned seats is:
5 x 4 x 3 x 2 x 1 = 120.
So, the answer is 120.
The answer is 120.
This can be calculated as follows:
There are 5 people in total, so the first seat can be filled by any of the 5 people.
Once the first seat is filled, there are only 4 people left that can fill the second seat.
After the second seat is filled, there are only 3 people left that can fill the third seat.
After the third seat is filled, there are only 2 people left that can fill the fourth seat.
Lastly, there is only 1 person left that can fill the fifth seat.
Therefore, the total number of ways you and 4 friends can sit in assigned seats is:
5 x 4 x 3 x 2 x 1 = 120.
So, the answer is 120.