a) Yobo's speed can be found by dividing the distance traveled (x-45) km by the time taken, which is 3 hours. Therefore, Yobo's speed is (x-45)/3 km/h.
b) Adoki's speed can be found by dividing the distance traveled (x+5) km by the time taken, which is 7 hours. Therefore, Adoki's speed is (x+5)/7 km/h.
c) The equation can be formed by equating Yobo's and Adoki's speed since they both cycle at the same rate. Therefore, (x-45)/3 = (x+5)/7.
d) To solve the equation (x-45)/3 = (x+5)/7, we can cross multiply:
7(x-45) = 3(x+5)
7x - 315 = 3x + 15
4x = 330
x = 330/4
x = 82.5
Therefore, the value of x is 82.5.
Yobo and Adoki are keenb cyclist. Yobo cycles (x-45)km from Surulere to Sagamu in 3 hours. Adoki cycle x+5 km from Sagamu to Ife in 7 hours . They both cycle at the same rate. Answer the following questions:
a) Write down Yobo's speed
b. Write down Adoki's speed
c. Form an equation in x
d. Solve the equation you formed in c
1 answer