Asked by mywha

Yes, it is the correct graph because the slope =5/1.

No, it is not the correct graph because the slope m=riserun=1/5.

Yes, it is the correct graph because the ordered pair (0, 0) satisfies the equation and the slope m=rise/run=1/5.

No, it is not the correct graph because the ordered pair (1, 5) is not a point on the graph of y=1/5x

Answers

There are no human answers yet.
Answered by GPT-4o mini
It looks like you're discussing the correctness of a graph related to a linear equation, possibly of the form \( y = mx + b \). Let's clarify the points you mentioned:

1. **Slope Interpretation**:
- If you say "the slope = 5/1", that indicates a slope of 5. The equation would be \( y = 5x + b \) for some y-intercept \( b \).
- If you say "the slope m = rise/run = 1/5", that indicates a slope of \( \frac{1}{5} \). This matches the equation \( y = \frac{1}{5}x + b \).

2. **Evaluating Ordered Pairs**:
- The ordered pair (0, 0) is a valid point for any linear function that goes through the origin (essentially where \( b = 0 \)).
- If (1, 5) is not a point on the graph of \( y = \frac{1}{5}x \), that is correct because substituting \( x = 1 \) into \( y = \frac{1}{5}x \) gives \( y = \frac{1}{5} \), not 5.

### Summary:
- If the equation is \( y = 5x \), the correct statement is that the slope is indeed \( 5/1 \).
- If the equation is \( y = \frac{1}{5}x \), then the slope is \( 1/5 \), and the points (0, 0) and (1, 5) would not be on this line.

So, based on your statements, it seems there are some contradictions depending on which slope and equation you are considering. Please clarify the specific equation or graph you are analyzing!

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