y = (x + 4)^2 - 5 when x = 4

Answer 1

To find the value of \( y \) when \( x = 4 \) in the equation \( y = (x + 4)^2 - 5 \), we simply substitute \( x \) with 4.

\[ y = (4 + 4)^2 - 5 \]

First, calculate \( 4 + 4 \):

\[ 4 + 4 = 8 \]

Next, square 8:

\[ 8^2 = 64 \]

Then, subtract 5 from 64:

\[ 64 - 5 = 59 \]

So, when \( x = 4 \), the value of \( y \) is:

\[ \boxed{59} \]